The number of moles of oxygen required for complete combustion depends on the specific substance being burned.
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The number of moles of oxygen required for complete combustion depends on the specific substance being burned. This is because different substances have different chemical formulas and require different amounts of oxygen to react completely. For example, the combustion of methane (CH4) requires 2 moles of oxygen (O2) to produce carbon dioxide (CO2) and water vapor (H2O).
According to Chemical Safety Facts, “Combustion is a rapid chemical reaction in which a fuel and an oxidant react to produce heat, light and combustion products.” This means that in order for combustion to occur, there must be a fuel (such as methane) and an oxidant (such as oxygen) present.
To better understand the amount of oxygen required for combustion, a table can be created to compare the chemical formulas and oxygen requirements of different substances. Here is an example:
Substance | Chemical Formula | Oxygen Required for Combustion |
---|---|---|
Methane | CH4 | 2 moles O2 |
Ethane | C2H6 | 3 moles O2 |
Propane | C3H8 | 5 moles O2 |
Butane | C4H10 | 6.5 moles O2 |
Octane | C8H18 | 25 moles O2 |
As Antoine Lavoisier, the French chemist and father of modern chemistry, once said, “Nothing is lost, nothing is created, everything is transformed.” This is particularly true in the case of combustion, where substances are transformed through a chemical reaction that requires a specific amount of oxygen to react completely.
Interesting facts about combustion and oxygen:
- The process of combustion is used in a variety of settings, including car engines, power plants, and stoves.
- The combustion of fossil fuels (such as coal, natural gas, and oil) is a major source of greenhouse gas emissions that contribute to climate change.
- Oxygen is not the only oxidant that can support combustion – other oxidants include fluorine, chlorine, and bromine.
- In some cases, the amount of oxygen required for combustion can be reduced by adding a catalyst to the reaction. For example, the use of a catalyst in car engines can help to reduce emissions.
Response via video
The video teaches how to find the necessary amounts of each reactant in a chemical equation by using the coefficients of the balanced equation. It specifically addresses the problem of determining how many moles of oxygen are needed to react with four moles of hydrogen and shows how to set up stoichiometrically equivalent quantities as conversion factors to solve the problem. Using the balanced equation for the combustion of hydrogen, it is determined that two moles of oxygen are needed to react with four moles of hydrogen.
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∴ 1 mole of methane requires 2 moles of Oxygen for complete combustion.
1.527 × 1024lmolecules
The complete combustion requires 1.527 × 1024lmolecules O2.
The complete combustion requires 1.527 × 1024lmolecules O2.
Wait… I see it before… Why?
You have to derive the chemical equation for the combustion of butane (C4H10)
The chemical equation must be something like C4H10 + O2 → CO2 +H2O (without the coefficients)
I don’t know whether you know how to balance the equation, but after balancing the equation, it should be something like this:
C4H10 + 6.5 O2 → 4 CO2 + 5 H2O
Each mole of butane needs 6.5 moles of oxygen, so 13 moles of oxygen is required for 2 moles of butane in a complete combustion.
This is copied and pasted from a comment I gave in Quora User’s answer to Element P has an electronic configuration of 2,8,6 element R has an electronic configuration of 2,8,8,1.What is likely to form if P and R combine? [ https://www.quora.com/Element-P-has-an-electronic-configuration-of-2-8-6-element-R-has-an-electronic-configuration-of-2-8-8-1-What-is-likely-to-form-if-P-and-R-combine/answers/26982074 ]
More interesting questions on the issue
5 moles required according to balanced reaction.
Propane is a hydrocarbon which is composed of carbon and hydrogen. It is also known as alkane with three carbon atoms. -From the above reaction it is evident that one equivalent of propane requires five equivalents of oxygen to generate three equivalents of carbon dioxide and four equivalents of water.